Thread Hash dereferenzieren
(9 answers)
Opened by SirLant at 2003-11-23 17:02
habe jetzt wieder die Struktur von oben
verwendet und es jetzt so gelöst: for my $key (keys %navi) { $navigation .= strong($key) . br (); for (keys %{$navi{$key}}) { $navigation .= br ().a({-href=>$navi{$key}{$_}},$_); } } Danke für eure Hilfe :) --Programming today is a race between Software Enginers striving to build bigger and better idiot-proof Programs,
and the Universe trying to produce bigger and better idiots. So far, the Universe is winning! |