klar geht das:
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#!/usr/bin/perl
use strict;
use warnings;
my @Eq = (
" ABC + DDE = FCF",
" CB + BGE = BCA",
" AEE + CBG = DGAE",
" ABC + CB = AEE",
" DDE + BGE = CBG",
" FCF + BCA = DGAE",
);
my @res = &Sol(@Eq);
foreach my $r (@res)
{
print join("; ", map { "$_ = $r->{$_}" } keys %{$r}), "\n";
}
sub Sol
{
my (@e) = @_;
my %pairs = ();
my @sol = ();
for (@e)
{
s!=!==!;
$pairs{$_} = 0 foreach (m!(\w)!g);
}
my @vars = keys %pairs;
my $count = scalar @vars;
while($pairs{$vars[$count-1]} < 10)
{
my $true = 0;
foreach my $e (@e)
{
while(my($k, $v) = each %pairs)
{
$e =~ s!$k!$v!g;
}
$true = eval $e;
last unless $true;
}
push @sol, {%pairs} if $true;
my $i = 0;
while($i < $count)
{
last if ++$pairs{$vars[$i]} < 10;
$pairs{$vars[$i]} = 0;
$i++;
}
}
return @sol;
}
wohl diese brute-force methode ziemlich ungeignet ist.
Komplexität O(n^10) mit n = Anzahl der Variablen