Thread [bash] Perl in Bash Skript (3 answers)
Opened by __1__ at 2012-10-10 11:46

GwenDragon
 2012-10-10 12:32
#162586 #162586
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Einfach den Heredoc-Trenner mit ' quoten.

Code (perl): (dl )
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#!/bin/bash

var=4711;

perl << 'X'
# neware this is the Perl var
$var = 13;
...
X

# now this the bash var!
echo $var;


Weiteres Example 19-7. Parameter substitution turned off
die Drachin Gwen

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