Thread perl6 Operatoren
(10 answers)
Opened by [E|B] at 2005-10-02 13:08
*lol* Das ist echt mega! :)
Gruß, Erik!
s))91\&\/\^z->sub{}\(\@new\)=>69\&\/\^z->sub{}\(\@new\)=>124\&\/\^z->sub{}\(\@new\)=>); $_.=qq~66\&\/\^z->sub{}\(\@new\)=>93~;for(@_=split(/\&\/\^z->sub{}\(\@new\)=>/)){print chr;} It's not a bug, it's a feature! - [CGI-World.de] |